
The deviation of the transverse wave travels satisfies: Y=25sinπ(14x−280t) with x and Y in meters and t in seconds. Fast wave propagation is .....
Physics Solution Mr. Dimpun:Y=25sinπ(14_xcoeff x−280_tcoeff t)v=coefficien tcoefficient xv=28014=20ms−1Please support and pray that we can build this blog and be useful for all.
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