The deviation of the transverse wave travels satisfies: $Y = 25\sin \pi (14x − 280t)$ with x and Y in meters and t in seconds. Fast wave propagation is .....
Physics Solution Mr. Dimpun:\[\begin{align*}Y &= 25\sin \pi (\underset{\textit{coeff x}}{\underline {{\color{Red} {14}}}x}-\underset{\textit{coeff t}}{\underline {{\color{Red} {280}}}t})\\\\v &= \frac{\textrm{coefficien t}}{\textrm{coefficient x}}\\ v &= \frac{ 280}{14}= 20ms^{-1}\end{align*}\]Please support and pray that we can build this blog and be useful for all.
